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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Introduction to Physics

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Introduction to Physics

Determine the power of a 100 watt bulb in CGS units.

Determine the power of a 100 watt100 \text{ watt} bulb in CGS units.

Options

  1. A107 erg/s10^7 \text{ erg/s}
  2. B105 erg/s10^5 \text{ erg/s}
  3. C1011 erg/s10^{11} \text{ erg/s}
  4. D109 erg/s10^9 \text{ erg/s}

Correct answer

D. 109 erg/s10^9 \text{ erg/s}

Step-by-step solution

Given power of the bulb is P=100 WP = 100 \text{ W}.

The SI unit of power is watt (W), which is equal to joule per second (J/s).

Therefore, P=100 J/sP = 100 \text{ J/s}.

In the CGS system, the unit of energy is erg, and 1 J=107 erg1 \text{ J} = 10^7 \text{ erg}.

Converting the power into CGS units:

P=100×107 erg/s=109 erg/sP = 100 \times 10^7 \text{ erg/s} = 10^9 \text{ erg/s}.
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