In a Calcutta laboratory, the height of the mercury column in a barometer was recorded as 75 cm . Determine this pressure in SI and CGS units using the following data: specific gravity of mercury = 13.6 , density of water = 10^3 kg/m ^3 , and g = 9.8 m/s ^2 at Calcutta. Use the formula Pressure = h g in usual symbols.

Step-by-step solution

Given h = 75 cm = 0.75 m Density of mercury, = 13.6 10^3 kg/m ^3 Acceleration due to gravity, g = 9.8 m/s ^2 In SI units, the pressure is given by: P = h g = 0.75 13.6 10^3 9.8 P = 99.96 10^3 N/m ^2 10 10^4 N/m ^2 In CGS units: h = 75 cm = 13.6 g/cm ^3 g = 9.8 m/s ^2 = 980 cm/s ^2 P = h g = 75 13.6 980 P = 999600 dyne/cm ^2 10 10^5 dyne/cm ^2