Identify the correct statement for B _ 2 H _ 6 from those given...

${B}_{2}{H}_{6}$ have $four2c - 2e$ bonds and $two3c - 2e$ bonds. Bridging bonds have larger bond length than terminal bonds. Angle between terminal bonds is more than angle between bridging bonds if all $4$ terminal bonds are in one plane then bridging bonds are in perpendicular plane.

$3{NaBH}_{4} + 4{BF}_{3}\mathop{\overset{ether}{⟶}}_{450K}3{NaBF}_{4} + 2{B}_{2}{H}_{6}$

Therefore we can say that only statement (C) and (D) are correct.