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JEE Main 202331 JanuaryEvening Shift
Exam
JEE Main
Year
2023
Date
31 January
Shift
Evening Shift
Subject
Chemistry
Chapter
Solid State

JEE Main 2023 · 31 January · Evening Shift · Chemistry · Solid State

A sample of a metal oxide has formula M _ 0 . 83 O _ 1 . 00 . The...

A sample of a metal oxide has formula M0.83O1.00{M}_{0 . 83}{O}_{1 . 00}. The metal MM can exist in two oxidation states +2+ 2 and +3+ 3. In the sample of M0.83O1.00{M}_{0 . 83}{O}_{1 . 00}, the percentage of metal ions existing in +2+ 2 oxidation state is %. (nearest integer)

Correct answer

0

Step-by-step solution

Let number of ions of M+2=x{M}^{+ 2} = x

Thus, as net charge has to be zero, M+3=0.83−x{M}^{+ 3} = 0 . 83 - x

⇒2x+3(0.83−x)+1(−2)=0⇒ 2x + 3 ( 0 . 83 - x ) + 1 ( - 2 ) = 0

⇒2x+2.49−3x−2=0⇒ 2x + 2 . 49 - 3x - 2 = 0

∴x=0.49∴ x = 0 . 49

% {M}^{2 +}\text{ions} = \dfrac{0 . 49}{0 . 83} \times 100 = 59 . 03

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