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JEE Main 20205 SeptemberMorning Shift
Exam
JEE Main
Year
2020
Date
5 September
Shift
Morning Shift
Subject
Chemistry
Chapter
Solid State

JEE Main 2020 · 5 September · Morning Shift · Chemistry · Solid State

A diatomic molecule X _ 2 has a body-centred cubic ( bcc )...

A diatomic molecule X2{X}_{2} has a body-centred cubic (bcc)( bcc ) structure with a cell edge of 300pm.300pm . The density of the molecule is 6.17gcm−3.6 . 17{gcm}^{- 3} . The number of molecules present in 200gofX2200g of {X}_{2} is :
(Avogadro constant \left({N}_{A}\right) = 6 \times {10}^{23}{mol}^{- 1}$)

Options

  1. A40NA40{N}_{A}
  2. B8NA8{N}_{A}
  3. C4NA4{N}_{A}
  4. D2NA2{N}_{A}

Correct answer

C. 4NA4{N}_{A}

Step-by-step solution

For BCC z=2z = 2

d=Z×MNA×Volumed = \dfrac{Z \times M}{{N}_{A} \times \text{Volume}}

6.17=2×M6.02×1023×[3×10−8]36 . 17 = \dfrac{2 \times M}{6 . 02 \times {10}^{23} \times {\left[3 \times {10}^{- 8}\right]}^{3}}

6.17=2×M6.02×2.76 . 17 = \dfrac{2 \times M}{6 . 02 \times 2 . 7}

M=50M = 50

No. of mole =20050=4= \dfrac{200}{50} = 4

No. of molecule =4NA= 4{N}_{A}

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