An element with molar mass 2 .7 × 10 − 2 kg mol − 1 forms a cubic unit cell with edge length 405 pm . If its density is 2 . 7 × 10 3 kg m - 3 , the radius of the element is approximately … … … . &#215

Question

An element with molar mass 2 .7 &#215; 10 &#8722; 2 kg mol &#8722; 1 forms a cubic unit cell with edge length 405 pm . If its density is 2 . 7 &#215; 10 3 kg m - 3 , the radius of the element is approximately &#8230; &#8230; &#8230; . &#215; 10 - 12 m (to the nearest integer)

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Density = Z &#215; M N a &#215; Volume d = Z &#215; 27 6 . 02 &#215; 10 23 &#215; 4 . 05 &#215; 10 - 3 3 2 . 7 = Z &#215; 27 6 . 02 &#215; 10 23 &#215; 4 . 05 &#215; 10 - 3 3 Z =4&#160;&#160;&#8658; fcc unit cell For fcc unit cell 4 r = 2 a r = 1 . 414 &#215; 405 4 = 143 . 1675 &#160; pm = 143 . 17 &#160; pm

An element with molar mass 2 .7 × 10 − 2 kg mol − 1 forms a cubic unit cell with edge length 405 pm . If its density is 2 . 7 × 10 3 kg m - 3 , the radius of the element is approximately … … … . × 10 - 12 m (to the nearest integer)

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An element with molar mass 2 .7 &#215; 10 &#8722; 2 kg mol &#8722; 1 forms a cubic unit cell with edge length 405 pm . If its density is 2 . 7 &#215; 10 3 kg m - 3 , the radius of the element is approximately &#8230; &#8230; &#8230; . &#215; 10 - 12 m (to the nearest integer)

Correct answer

Step-by-step solution

More from Solid State

An element with molar mass 2 .7 × 10 − 2 kg mol − 1 forms a cubic unit cell with edge length 405 pm . If its density is 2 . 7 × 10 3 kg m - 3 , the radius of the element is approximately … … … . × 10 - 12 m (to the nearest integer)