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JEE Main 201912 AprilEvening Shift
Exam
JEE Main
Year
2019
Date
12 April
Shift
Evening Shift
Subject
Chemistry
Chapter
Solid State

JEE Main 2019 · 12 April · Evening Shift · Chemistry · Solid State

The ratio of number of atoms present in a simple cubic, body...

The ratio of number of atoms present in a simple cubic, body centered cubic and face centered cubic structure are, respectively :The ratio of number of atoms present in a simple cubic, body centered cubic and face centered cubic structure are,The ratio of number of atoms present in a simple cubic, body centered cubic and face centered cubic structure are,The ratio of number of atoms present in a simple cubic, body centered cubic and face centered cubic structure are,

Options

  1. A4:2:14: 2: 1
  2. B1:2:41: 2: 4
  3. C4:2:34: 2: 3
  4. D8:1:68: 1: 6

Correct answer

B. 1:2:41: 2: 4

Step-by-step solution

ZSC=8×18=1{Z}_{SC} = 8 \times \dfrac{1}{8} = 1

[Atoms are only at the corners]

ZBCC=8×18+1=1+1=2{Z}_{BCC} = 8 \times \dfrac{1}{8} + 1 = 1 + 1 = 2

[Atoms are at the corners and at the body center]

ZFCC=8×18+6×12=1+3=4{Z}_{FCC} = 8 \times \dfrac{1}{8} + 6 \times \dfrac{1}{2} = 1 + 3 = 4

[Atoms are at the corners and at the face centers]

Here, Z= effective number of atoms in the unit cell.

Therefore, ZSC:ZBCC:ZFCC=1:2:4{Z}_{SC} : {Z}_{BCC} : {Z}_{FCC} = 1: 2: 4

The ratio of number of atoms present in a simple cubic, body centered cubic and face centered cubic structure are,
The ratio of number of atoms present in a simple cubic, body centered cubic and face centered cubic structure are,
The ratio of number of atoms present in a simple cubic, body centered cubic and face centered cubic structure are,
SC:BCC:FCC=1:2:4SC: BCC: FCC = 1: 2: 4

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