An element has a face-centered cubic (fcc) structure with a cell...

An element has a face-centered cubic

\left(fcc\right)

structure with a cell edge of

a

. The distance between the centres of two nearest tetrahedral voids in the lattice is An element has a face-centered cubic (fcc) structure with a cell edge of a . The distance between the centres of two

An element has a face-centered cubic (fcc) structure with a cell edge of a . The distance between the centres of two

Options

A $\dfrac{a}{2}$
B $\dfrac{3}{2}a$
C $a$
D $\sqrt{2a}$

Correct answer

A. $\dfrac{a}{2}$

Step-by-step solution

symmetrical cube<br /><img src="https://cdn-question-pool.Quantrex.app/pyq/jee_main/78e8318c-5f93-454f-8b38-f9c6d87eec7b-image25.png" /><br /><img src="https://cdn-question-pool.Quantrex.app/pyq/jee_main/5b656f1c-b9b8-4ba7-a0ef-8f526219ebf8-image26.png" /><br />Distance between two

\text{TV} = \text{a} - \left(\dfrac{\text{a}}{\text{4}}\text{+}\dfrac{\text{a}}{\text{4}}\right)

<br />

= \dfrac{a}{2}

<br />Correct option is \left(C\right)

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