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JEE Main 201212 MayOnline
Exam
JEE Main
Year
2012
Date
12 May
Mode
Online
Subject
Chemistry
Chapter
Solid State

JEE Main 2012 · 12 May · Online · Chemistry · Solid State

The radius of a calcium ion is 94 pm and of the oxide ion is 146 pm...

The radius of a calcium ion is 94pm94 \mathrm{pm} and of the oxide ion is 146pm146 \mathrm{pm}. The possible crystal structure of calcium oxide will be

Options

  1. Atetrahedral
  2. Btrigonal
  3. Coctahedral
  4. Dpyramidal

Correct answer

C. octahedral

Step-by-step solution

As per formula,  radius ratio = radius of cation  radius of anion =94146=0.643\begin{aligned}\text{ radius ratio }& =\frac{\text{ radius of cation }}{\text{ radius of anion }}\\ & =\frac{94}{146}=0.643 \end{aligned}Since$ the value is between 0.414-0.732 hence the coordination no. will be 6 and geometry will be octahedral.
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