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( CaCO ₃( ~s )+2 HCl ( aq ) CaCl ₂( aq )+ CO ₂( ~g ) H ₂ O ( l ) ) Consider the above reaction, what mass of ( CaCl ₂ ) will be formed if 250 mL of 0.76 M HCl reacts with 1000 g of ( CaCO ₃ ) ? (Given : Molar mass of ( Ca , C , O , H ) and Cl are 40, (12,16,1 ) and (35.5 ~g ~mol ⁻¹ ), respectively)

Options

  1. A3.908 g
  2. B2.636 g
  3. C10.545 g
  4. D5.272 g

Correct answer

C. 10.545 g

Step-by-step solution

( aligned & CaCO ₃+2 HCl CaCl ₂+ CO ₂+ H ₂ O & Moles of CaCO ₃= 1000 100 =10 aligned ) Moles of ( HCl =0.76 250 1000 =0.19 ) (L.R.) Moles of ( CaCl ₂ ) formed (= 0.19 2 ) Mass of ( CaCl ₂= 0.19 2 111=10.545 gm )

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