JEE Main 20252 AprilMorning Shift
- Exam
- JEE Main
- Year
- 2025
- Date
- 2 April
- Shift
- Morning Shift
- Subject
- Chemistry
- Chapter
- Some Basic Concepts of Chemistry
JEE Main 2025 · 2 April · Morning Shift · Chemistry · Some Basic Concepts of Chemistry
( CaCO _ 3 ( ~s)+2 HCl(aq) arrow CaCl _ 2 ( aq)+CO _ 2 ( ~g) H _ 2...
(\mathrm{CaCO}}_{3}( \mathrm{~s})+2 \mathrm{HCl}(\mathrm{aq}) \rightarrow \mathrm{CaCl}}_{2}(\mathrm{aq})+\mathrm{CO}}_{2}( \mathrm{~g}) \mathrm{H}}_{2} )
Consider the above reaction, what mass of (\mathrm{CaCl}}_{2}) will be formed if 250 mL of 0.76 M HCl reacts with 1000 g of (\mathrm{CaCO}}_{3}) ?
(Given : Molar mass of () and Cl are 40, and (35.5 ), respectively)
Consider the above reaction, what mass of (\mathrm{CaCl}}_{2}) will be formed if 250 mL of 0.76 M HCl reacts with 1000 g of (\mathrm{CaCO}}_{3}) ?
(Given : Molar mass of () and Cl are 40, and (35.5 ), respectively)
Options
- A3.908 g
- B2.636 g
- C10.545 g
- D5.272 g
Correct answer
C. 10.545 g
Step-by-step solution
)Moles of (\mathrm{HCl}=0.76 \times \frac{250}{1000}=0.19) (L.R.)Moles of (\mathrm{CaCl}_2) formed (=\frac{0.19}{2})Mass of (\mathrm{CaCl}_2=\frac{0.19}{2} \times 111=10.545 \mathrm{gm})$