The molarity of a 70 \% (mass / mass) aqueous solution of a monobasic acid (X) is __________ × 10^ -1 M(Nearest integer) [Given: Density of aqueous solution of (X) is 1.25 ~g ~mL^ -1 Molar mass of the acid is 70 ~g

Correct answer: 0 Moles of solute = (70)/(70)= 1Volume of solution =(100)/(1.25)=80 ~mL aligned & M=(1)/(80) × 1000=12.5 & M=125 × 10^ -1 aligned

JEE Main 202528 JanuaryMorning Shift

JEE Main 2025 · 28 January · Morning Shift · Chemistry · Some Basic Concepts of Chemistry

The molarity of a 70 \% (mass / mass) aqueous solution of a...

The molarity of a

70 \%

(mass

/

mass) aqueous solution of a monobasic acid

(\mathrm{X})

is __________

\times 10^{-1}

M(Nearest integer) [Given: Density of aqueous solution of (X) is

1.25 \mathrm{~g} \mathrm{~mL}^{-1}

Molar mass of the acid is

70 \mathrm{~g} \mathrm{~mol}^{-1}

]

Moles of solute =

\frac{70}{70}=

1Volume of

solution =\frac{100}{1.25}=80 \mathrm{~mL}

\begin{aligned} & M=\frac{1}{80} \times 1000=12.5 \\ & M=125 \times 10^{-1} \end{aligned}