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JEE Main 202528 JanuaryMorning Shift
Exam
JEE Main
Year
2025
Date
28 January
Shift
Morning Shift
Subject
Chemistry
Chapter
Some Basic Concepts of Chemistry

JEE Main 2025 · 28 January · Morning Shift · Chemistry · Some Basic Concepts of Chemistry

Quantitative analysis of an organic compound (X) shows following %...

Quantitative analysis of an organic compound (X) shows following % composition. C : 14.5%14.5 \% Cl : 64.46% H: 1.8 % (Empirical formula mass of the compound (X)(\mathrm{X}) is __________ ×10−1\times 10^{-1} (Given molar mass in gmol−1\mathrm{g} \mathrm{mol}^{-1} of C:12,H:1,O:16,Cl:35.5\mathrm{C}: 12, \mathrm{H}: 1, \mathrm{O}: 16, \mathrm{Cl}: 35.5)

Correct answer

0

Step-by-step solution

\begin{array}{ll:cccl} & \mathrm{C} & \mathrm{Cl} & \mathrm{H} & \mathrm{O} & \\ \text{ %mass } & 14.5 & 64.46 & 1.8 & 19.24\end{array} Molar ratio 14.512\frac{14.5}{12} \quad 64.4635.5\frac{64.46}{35.5} \quad 1.81\frac{1.8}{1} \quad 19.2416\frac{19.24}{16}1.21.81.81.2 Minimum 2332 integral ratio \begin{aligned}&\begin{array}{ccccc}& 1.2 & 1.8 & 1.8 & 1.2 \\ \text{ Minimum }& 2 & 3 & 3 & 2 \end{array}\\ &\text{ integral ratio } \end{aligned}$\begin{aligned}& \text{ Empiricial formula }=\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{Cl}_{3} \mathrm{O}_{2} \\ & \text{ Mass }=165.5 \\ & \text{ Mass }=1655 \times10^{-1}\end{aligned}
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