The elemental composition of a compound is 54.2 \% C, 9.2 \% H and 36.6 \% O . If the molar mass of the compound is 132 ~g ~mol^ -1 , the molecular formula of the compound is : [Given : The relative atomic mass of C: H

Correct answer: D. C_6 H_ 12 O_3 Molecular mass of compound =132 ~g ~mol^ -1 Molecular formula of compound is (C_2 H_4 O)_n n= Molecular mass EF mass =(132)/(44)=3 Molecular formula of compound is C_6 H_ 12 O_3

JEE Main 202524 JanuaryEvening Shift

Exam: JEE Main
Year: 2025
Date: 24 January
Shift: Evening Shift
Subject: Chemistry
Chapter: Some Basic Concepts of Chemistry

JEE Main 2025 · 24 January · Evening Shift · Chemistry · Some Basic Concepts of Chemistry

The elemental composition of a compound is 54.2 \% C, 9.2 \% H and...

The elemental composition of a compound is

54.2 \% \mathrm{C}, 9.2 \% \mathrm{H}

and

36.6 \% \mathrm{O}

. If the molar mass of the compound is

132 \mathrm{~g} \mathrm{~mol}^{-1}

, the molecular formula of the compound is : [Given : The relative atomic mass of

\mathrm{C}: \mathrm{H}: \mathrm{O}=12: 1: 16

] $The elemental composition of a compound is 54.2 \% C, 9.2 \% H and 36.6 \% O . If the molar mass of the compound is 132$

Options

A $\mathrm{C}_4 \mathrm{H}_9 \mathrm{O}_3$
B $\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_6$
C $\mathrm{C}_4 \mathrm{H}_8 \mathrm{O}_2$
D $\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_3$

Correct answer

D. $\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_3$

Step-by-step solution

$The elemental composition of a compound is 54.2 \% C, 9.2 \% H and 36.6 \% O . If the molar mass of the compound is 132$
Molecular mass of compound

=132 \mathrm{~g} \mathrm{~mol}^{-1}

Molecular formula of compound is \left(\mathrm{C}_2 \mathrm{H}_4 \mathrm{O}\right)_n \mathrm{n}=\frac{\text{ Molecular mass }}{\mathrm{EF} \text{ mass }}=\frac{132}{44}=3 \therefore

Molecular formula of compound is

\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_3

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