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JEE Main202430 Jan 2024Morning ShiftChemistrySome Basic Concepts of ChemistryActual

0 . 05 cm thick coating of silver is deposited on a plate of 0 . 05 m 2 area. The number of silver atoms deposited on plate are _______ × 10 23 . (At mass Ag = 108 , d = 7 . 9 g cm - 3 Round off to the nearest integer.

Correct answer

0

Step-by-step solution

Volume of silver coating = 0 . 05 × 0 . 05 × 10000 = 25 cm 3 Given, Density = 7 . 9 g cm - 3 Density = Mass/ Volume Mass of silver deposited = 25 × 7 . 9 g Moles of silver atoms = mass / molar mass = 25 × 7 . 9 108 Number of silver atoms = 25 × 7 . 9 108 × 6 . 023 × 10 23 = 11 . 01 × 10 23 Ans. 11

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