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JEE Main202427 Jan 2024Evening ShiftChemistrySome Basic Concepts of ChemistryActual

Volume of 3 M NaOH (formula weight 40 g mol - 1 ) which can be prepared from 84 g of NaOH is ____ × 10 - 1 dm 3 .

Correct answer

0

Step-by-step solution

Number of moles = Mass / Molar mass​ Molar mass of NaOH= 40 g/mol By Using the definition of molarity to find the volume of the solution: Molarity= Number of moles of solute Volume of solution (in liters) M = n NaOH V sol ( in L ) ⇒ 3 = ( 84 / 40 ) V ⇒ V = 0 . 7 L = 7 × 10 - 1 L

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