C s + O 2 g → CO 2 g + 400 kJ C s + 1 2 O 2 g → CO g + 100 kJ When coal of purity 60 % is allowed to burn in presence of insufficient oxygen, 60 % of carbon is converted into ' CO ' and the remaining is converted into ' CO 2 '. The heat generated when 0 . 6 kg of coal is burnt is

Step-by-step solution

C S + O 2 g → CO 2 g + 400   kJ 1 mole C s + 1 2 O 2 g → CO g + 100   kJ         . . . 2 0 . 6 Kg × 1000 = 600 gm Mass of 60 % pure coal = 600 × 60 100 (Pure Carbon) = 360 gm Number   of   moles = 360 12 = 30   moles   of   pure   carbon Moles of 60% pure Carbon converted into CO 2 = 30 - 30 × 60 100 = 12 mole and Moles of 60% pure carbon converted in to CO = 30 × 60 100 = 18 mole Energy generated during 2 equation = 18 &#21