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A 1 . 84 mg sample of polyhydric alcoholic compound ' X ' of molar mass 92 . 0 g / mol gave 1 . 344 mL of H 2 gas at STP. The number of alcoholic hydrogen present in compound ' X ' is

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Number of moles of alcoholic compound = Given   mass Molar   mass   =   1 . 84 × 10 - 3 92 . 0   =   2 × 10 - 5   moles Number of moles of hydrogen gas produced =   Volume   of   gas   at   STP 22400   ml   =   1 . 344 22400   =   6 × 10 - 5   moles Monohydric alcohol will react with active metal to give 1 2   mole of hydrogen gas. Since per mole of given alcohol is giving 3 moles of hydrogen gas. So number

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