Hemoglobin contains 0 . 34 % of iron by mass. The number of Fe atoms in 3 . 3 g of hemoglobin is (Given : Atomic mass of Fe is 56 u , N A in 6 . 022 × 10 23 mol - 1 )

Step-by-step solution

Mass of haemoglobin = 3 . 3 g Mass of iron atoms = 0 . 34 100 × 3 . 3 = 0 . 01122 g 56   g   of iron contains = 1 mole of iron or 6 . 023   ×   10 23 atoms Number of moles of atoms= Mass   atomic   mass Number of moles of 0 . 01122 g of iron is Number of moles = 0 . 01122 g 56 g = 0 . 00020 moles Number of atoms =Number of moles × avogadro number No. of Fe atoms = 0 . 00020 × 6 . 022 × 10 23 = 1 . 2046   ×   10 20