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JEE Main 202229 JuneEvening Shift
Exam
JEE Main
Year
2022
Date
29 June
Shift
Evening Shift
Subject
Chemistry
Chapter
Some Basic Concepts of Chemistry

JEE Main 2022 · 29 June · Evening Shift · Chemistry · Some Basic Concepts of Chemistry

Using the rules for significant figures, the correct answer for the...

Using the rules for significant figures, the correct answer for the expression 0.02858×0.1120.5702\dfrac{0 . 02858 \times 0 . 112}{0 . 5702} will be:

Options

  1. A0.0056130 . 005613
  2. B0.005610 . 00561
  3. C0.00560 . 0056
  4. D0.0060 . 006

Correct answer

B. 0.005610 . 00561

Step-by-step solution

In multiplication and division, the result must be reported with no more significant figures as in the measurement with few significant figures

0.02858×0.1120.5702=0.000561\dfrac{0 . 02858 \times 0 . 112}{0 . 5702} = 0 . 000561

(Or) Reported answer should not be more precise than the least precise term in calculations, so there should be three significant figures in reported answer.

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