JEE Main202229 Jun 2022Morning ShiftChemistrySome Basic Concepts of ChemistryActual
Production of iron in blast furnace follows the following equation Fe 3 O 4 s + 4 CO g → 3 Fe l + 4 CO 2 g when 4 . 640 kg of Fe 3 O 4 and 2 . 520 kg of CO are allowed to react then the amount of iror (in g ) produced is : [Given: Molar Atomic mass gmol - 1 : Fe = 56 Molar Atomic mass gmolm - 1 : O = 16 Molar Atomic mass gmolm - 1 : C = 12 ]
Options
- A1400
- B2200
- C3360
- D4200
Correct answer
C. 3360
Step-by-step solution
Moles of Fe 3 O 4 = 4 . 640 × 10 3 232 = 20 Moles of CO = 2 . 52 × 10 3 28 = 90 So limiting Reagent = Fe 3 O 4 So moles of Fe formed = 60 Weight of Fe = 60 × 56 = 3360 gms