Compound A contains 8 . 7 % Hydrogen, 74 % Carbon and 17 . 3 % Nitrogen. The molecular formula of the compound is, Given : Atomic masses of C, H and N are 12, 1 and 14 amu respectively. The molar mass of the compound A

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Correct answer: D. C _ 10 H _ 14 N _ 2

C 74 % (74)/(12) = 6 . 16 (6 . 16)/(1 . 23) = 5 N 17 . 3 % (17 . 3)/(14) = 1 . 23 (1 . 23)/(1 . 23) = 1 H 8 . 7 % (8 . 7)/(1) = 8 . 7 (8 . 7)/(1 . 23) = 7 Emperical formula = C _ 5 NH _ 7 Emperical weight = 81 Multiplying factor = (162)/(81) = 2 Molecular formula= (Empiricalformula) _ n Molecular formula= ( C _ 5 NH _ 7 ) _ 2 Molecular formula = C _ 10 N _ 2 H _ 14

$C$	$74 %$	$\dfrac{74}{12} = 6 . 16$	$\dfrac{6 . 16}{1 . 23} = 5$
$N$	$17 . 3 %$	$\dfrac{17 . 3}{14} = 1 . 23$	$\dfrac{1 . 23}{1 . 23} = 1$
$H$	$8 . 7 %$	$\dfrac{8 . 7}{1} = 8 . 7$	$\dfrac{8 . 7}{1 . 23} = 7$

Compound A contains 8 . 7 % Hydrogen, 74 % Carbon and 17 . 3 %...

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