116g of a substance upon dissociation reaction, yields 7 . 5g of...

$\left(OrganicCompoundcontaingC, H, O\right)\overset{dissociati on}{⟶}\mathop{H}_{7 . 5gram} + \mathop{O}_{60gram} + \mathop{C}_{48 . 5gram}$ of H in the given organic compound $= \dfrac{7 . 5}{116} \times 100 = 6 . 465$

(A) % of $H = \dfrac{4}{60} \times 100 = 6 . 6$

(B) % of $H = \dfrac{2}{30} \times 100 = 6 . 6$%

(c) % of $H = \dfrac{6}{62} \times 100 = 7 . 677$%

(D) % of $H = \dfrac{4}{44} \times 100 = 9 . 09$%

The percentage of Hydrogen in the given organic compound is equal to $6 . 465$ which is approximately equal to the percentage of hydrogen in ${CH}_{3}COOHandHCHO$.