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JEE Main 202127 AugustEvening Shift
Exam
JEE Main
Year
2021
Date
27 August
Shift
Evening Shift
Subject
Chemistry
Chapter
Some Basic Concepts of Chemistry

JEE Main 2021 · 27 August · Evening Shift · Chemistry · Some Basic Concepts of Chemistry

100g of propane is completely reacted with 1000g of oxygen. The...

100g100g of propane is completely reacted with 1000g1000g of oxygen. The mole fraction of carbon dioxide in the resulting mixture is x×10−2x \times {10}^{- 2}. The value of xx is (Nearest integer)

Correct answer

0

Step-by-step solution

C3H8(g)+5O2(g)⟶3CO2(g)+4H2O(ℓ){C}_{3}{H}_{8 ( g )} + 5{O}_{2 ( g )} ⟶ 3{CO}_{2 ( g )} + 4{H}_{2}{O}_{( ℓ )}

{t=02.27mole31.25mol\begin{cases}t = 0 & 2 . 27mole & 31 . 25mol\end{cases}

{t=∞019.9mol6.81mol9.08mol\begin{cases}t = \infty & 0 & 19 . 9mol & 6 . 81mol & 9 . 08mol\end{cases}

mole fraction of CO2{CO}_{2} in the final reaction mixture (heterogeneous)

XCO2=6.8119.9+6.81+9.08{X}_{{CO}_{2}} = \dfrac{6 . 81}{19 . 9 + 6 . 81 + 9 . 08}

=0.1902=19.02×10−2⇒19= 0 . 1902 = 19 . 02 \times {10}^{- 2} ⇒ 19

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