A 6 . 50 molal solution of KOH aq . has a density of 1 . 89 g cm - 3 . The molarity of the solution is mol dm - 3 . (Round off to the Nearest Integer). [Atomic masses: K : 39 . 0 u ; O : 16 . 0 u ; H : 1 . 0 u ]

Step-by-step solution

6 . 5 molal KOH = 1000   gm solvent has 6 . 5 moles KOH so, wt. of solute = 6 . 5 × 56 = 364   gm wt. of solution = 1000 + 364 = 1364 Volume of solution = 1364 1 . 89   m ℓ Molarity = mole   of   solute V solution     in   Litre = 9 . 00