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JEE Main202126 Feb 2021Evening ShiftChemistrySome Basic Concepts of ChemistryActual

The NaNO 3 weighed out to make 50   mL of an aqueous solution containing 70 . 0   mg   Na + per mL is_ g . (Rounded off to the nearest integer) [Given : Atomic weight in gmol - 1 - Na   :   23 ;   N   :   14 ;   O   :   16 ]

Correct answer

0

Step-by-step solution

Na + present in 50   ml = 70   mg 1   ml × 50   ml = 3500   mg = 3 . 5   gm moles of Na + = 3 . 5 23 = moles of NaNO 3 weight of NaNO 3 = 3 . 5 23 × 85 = 12 . 993   gm   = 13   gm

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