The volume (inmL) of 0.125M AgNO _ 3 required to quantitatively precipitate chloride ions in 0.3g of [Co (N H _ 3 ) _ 6 ]C l _ 3 is __________. [Co (N H _ 3 ) _ 6 ] M C l _ 3 = 267.46g / mol AgNO M _ 3 = 169.87g / mol

Correct answer: 0 [ ML _ 6 ] Cl _ 3 _ 0 .3 g + 3 AgNO _ 3 _ Vml, 0 .125 M →3AgCl (0 .3)/(267 .46) × 3 = 0 .125 × V × 10 ^ - 3 Or, V = (0 .3 × 3 × 1000)/(267 .46 × 0 .125) = 26 .92 ml

JEE Main 20208 JanuaryMorning Shift

Exam: JEE Main
Year: 2020
Date: 8 January
Shift: Morning Shift
Subject: Chemistry
Chapter: Some Basic Concepts of Chemistry

JEE Main 2020 · 8 January · Morning Shift · Chemistry · Some Basic Concepts of Chemistry

The volume (inmL) of 0.125M AgNO _ 3 required to quantitatively...

The volume $\left(inmL\right)$ of 0.125M{AgNO}_{3} required to quantitatively precipitate chloride ions in 0.3g of $\left[Co{\left(N{H}_{3}\right)}$ _{6}\right]C{l}_{3} $is __________.<br />\left[Co{\left(N{H}_{3}\right)}_{6}\right] M C{l}_{3} = 267.46g / mol$
${AgNO M}_{3} = 169.87g / mol$

Report the nearest integer as the answer.

Correct answer

Step-by-step solution

\mathop{\left[{ML}_{6}\right]{Cl}_{3}}_{0 .3 g} + \mathop{3{AgNO}_{3}}_{Vml, 0 .125 M}\to3AgCl

\dfrac{0 .3}{267 .46} \times 3 = 0 .125 \times V \times {10}^{- 3}

Or,

V = \dfrac{0 .3 \times 3 \times 1000}{267 .46 \times 0 .125} = 26 .92 ml

Practice Some Basic Concepts of Chemistry on Quantrex Academy →

More from Some Basic Concepts of Chemistry

Match List-I with List-II. List-I Mass of substance List-II Number of atoms A. 1.8 mg… JEE Main 2026 Which of the following contain the same number of atoms ? (Given : Molar mass in g mol ^… JEE Main 2026 An oxide of iron contains 69.9\% iron, its empirical formula, is: (Given: Molar mass of… JEE Main 2026 What volume of hydrogen gas at STP would be liberated by action of 50 mL of H_2SO_4 of… JEE Main 2026 How many grams of residue is obtained by heating 2.76 g of silver carbonate? (Given… JEE Main 2026 The correct order of total number of atoms present in (A) 2 moles of cyclohexane (B) 684… JEE Main 2026 Number of moles and number of molecules in 1.4187 L of SO_2 at STP respectively are: JEE Main 2026 The ratio of mass percentage (w/w) of C : H in a hydrocarbon is 12 : 1 . It has two… JEE Main 2026 Full Some Basic Concepts of Chemistry list All JEE Main PYQs