JEE Main20208 Jan 2020Morning ShiftChemistrySome Basic Concepts of ChemistryActual
The volume i n m L of 0.125 M A g N O 3 required to quantitatively precipitate chloride ions in 0.3 g of C o N H 3 6 C l 3 is __________. C o N H 3 6 M C l 3 = 267.46 g / m o l A g N O M 3 = 169.87 g / m o l Report the nearest integer as the answer.
Correct answer
0
Step-by-step solution
ML 6 Cl 3 0 .3 g + 3 AgNO 3 V   ml ,   0 .125   M → 3 AgCl 0 .3 267 .46 × 3 = 0 .125 × V × 10 - 3 Or, V = 0 .3 × 3 × 1000 267 .46 × 0 .125 = 26 .92 ml