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JEE Main201910 Apr 2019Evening ShiftChemistrySome Basic Concepts of ChemistryActual

The minimum amount of O 2 g consumed per gram of reactant is for the reaction: (Given atomic mass: F e = 56 , O = 16 , M g = 24 , P = 31 , C = 12 , H = 1 )

Options

  1. AP 4 s + 5 O 2 g → P 4 O 10 s
  2. B2   M g s + O 2 g → 2 M g O s
  3. C4 F e s + 3 O 2 g → 2 F e 2 O 3 s
  4. DC 3 H 8 g + 5 O 2 g → 3 C O 2 g + 4 H 2 O ( l )

Correct answer

C. 4 F e s + 3 O 2 g → 2 F e 2 O 3 s

Step-by-step solution

(i) 5 mole O 2 required = 1 mole of P 4 =124 gm P 4 for per gram, O 2   required = 5 124   m o l e   (ii) 1 mole O 2 required = 2 mole Mg = 2 × 24   g m for per gram, O 2   required = 1 48   m o l e (iii) 3 mole O 2 required = 2 mole Fe = 4 × 56   g m for per gram Fe, O 2 required = 3 112 × 2 mole (iv) 5 mole O 2 required - = 1 mole C 3 H 8 =44 gm C 3 H 8 per gram C 3 H 8 ,   O 2 required = 5 44 mole

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