Exam

JEE Main

Year

2019

Date

10 April

Shift

Morning Shift

Subject

Chemistry

Chapter

Some Basic Concepts of Chemistry

JEE Main 2019 · 10 April · Morning Shift · Chemistry · Some Basic Concepts of Chemistry

At 300K and 1 atmospheric pressure, 10mL of a hydrocarbon required...

At $300K$ and $1$ atmospheric pressure, $10mL$ of a hydrocarbon required $55mL$ of ${O}_{2}$ for complete combustion, and $40mL$ of $C{O}_{2}$ is formed. The formula of the hydrocarbon is:

Step-by-step solution

Let hydrocarbon is ${C}_{x}{H}_{y}$

$10x = 40$ ; x = 4 and $10\left(x + \dfrac{y}{4}\right) = 55$
\left(x + \dfrac{y}{4}\right) = \dfrac{55}{10}$<br />$x + \dfrac{y}{4} = 5.5$<br />Put the value of$x$<br />$4 + \dfrac{y}{4} = 5.5$<br />$\dfrac{y}{4} = 5 . 5 - 4$<br />$\dfrac{y}{4} = 1 . 5 then $y = 6$
Hence hydrocarbon is ${C}_{4}{H}_{6}$