A sample of NaClO ₃ is converted by heat to NaCl with a loss of 0.16 ~g of oxygen. The residue is dissolved in water and precipitated as AgCl . The mass of AgCl (in g ) obtained will be: (Given: Molar mass of AgCl =143.5 ~g ~mol ⁻¹ )

Step-by-step solution

No. of moles of oxygen in 0.16 ~g of oxygen molecule = 0.16 ~g 32 ~g / mol =0.005 ~mole 2 NaClO ₃ 2 NaCl +3 O ₂ According to the reaction, 3 moles of O ₂=2 moles of NaCl =2 moles of AgCl Molar mass of AgCl =143.5 ~g / mol 0.005 moles of O ₂ will ppt. =0.005 2 3 moles AgCl =0.0033 moles of AgCl Mass of AgCl (in g ) obtained will be =143.5 ~g / mol 0.0033 moles =0.48 ~g .