JEE Main 201815 AprilMorning ShiftOnline

JEE Main 2018 · 15 April · Morning Shift · Online · Chemistry · Some Basic Concepts of Chemistry

A sample of NaClO_3 is converted by heat to NaCl with a loss of...

A sample of

\mathrm{NaClO}_3

is converted by heat to

\mathrm{NaCl}

with a loss of

0.16 \mathrm{~g}

of oxygen. The residue is dissolved in water and precipitated as

\mathrm{AgCl}

. The mass of

\mathrm{AgCl}

(in

\mathrm{g}

) obtained will be: (Given: Molar mass of

\mathrm{AgCl}=143.5 \mathrm{~g} \mathrm{~mol}^{-1}

)

Options

D. $0.48$

No. of moles of oxygen in

0.16 \mathrm{~g}

of oxygen molecule

=\frac{0.16 \mathrm{~g}}{32 \mathrm{~g} / \mathrm{mol}}=0.005 \mathrm{~mole} 2 \mathrm{NaClO}_3 \stackrel{\Delta}{\longrightarrow} 2 \mathrm{NaCl}+3 \mathrm{O}_2

According to the reaction,

3

moles of

\mathrm{O}_2=2

moles of

\mathrm{NaCl} =2

moles of

\mathrm{AgCl}

Molar mass of

\mathrm{AgCl}=143.5 \mathrm{~g} / \mathrm{mol} 0.005

moles of

\mathrm{O}_2

will ppt.

=0.005 \times \frac{2}{3}

moles

\mathrm{AgCl}=0.0033 \text{ moles of } \mathrm{AgCl}\therefore

Mass of

\mathrm{AgCl}

(in

\mathrm{g}

) obtained will be

=143.5 \mathrm{~g} / \mathrm{mol} \times 0.0033

moles

=0.48 \mathrm{~g}