A sample of NaClO 3 is converted by heat to NaCl with a loss of 0 . 16 g of oxygen. The residue is dissolved in water and precipitated as AgCl . The mass of AgCl (in g ) obtained will be: (Given: Molar mass of AgCl = 143 .5 g mol - 1 )

Step-by-step solution

2 NaClO 3 → ∆ 2 NaCl + 3 O 2 2   moles   of   NaCl = 3   moles   of   oxygen n NaCl = 0 .16 32 × 2 3 = 1 200 × 2 3 = 1 300 The number of moles of NaCl = The number of moles of AgCl 1 300 = n AgCl Weight of AgCl = 1 300 × 108 + 35.5 = 1 300 × 143.5 = 0 .48   g