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JEE Main 201815 April
Exam
JEE Main
Year
2018
Date
15 April
Subject
Chemistry
Chapter
Some Basic Concepts of Chemistry

JEE Main 2018 · 15 April · Chemistry · Some Basic Concepts of Chemistry

A sample of NaClO _ 3 is converted by heat to NaCl with a loss of 0...

A sample of NaClO3{NaClO}_{3} is converted by heat to NaClNaCl with a loss of 0.16g0 . 16g of oxygen. The residue is dissolved in water and precipitated as AgClAgCl. The mass of AgClAgCl (in gg) obtained will be: (Given: Molar mass of AgCl=143.5gmol−1AgCl = 143 .5 g{mol}^{- 1})

Options

  1. A0.350 . 35
  2. B0.540 . 54
  3. C0.410 . 41
  4. D0.480 . 48

Correct answer

D. 0.480 . 48

Step-by-step solution

2NaClO3→∆2NaCl+3O22{NaClO}_{3}\overset{∆}{\to}2NaCl + 3{O}_{2}
2molesofNaCl=3molesofoxygen2molesofNaCl = 3molesofoxygen
nNaCl=0.1632×23=1200×23=1300{n}_{NaCl} = \dfrac{0 .16}{32} \times \dfrac{2}{3} = \dfrac{1}{200} \times \dfrac{2}{3} = \dfrac{1}{300}
The number of moles of NaCl=NaCl =The number of moles of AgClAgCl
1300=nAgCl\dfrac{1}{300} = {n}_{AgCl}
Weight of AgCl=1300×[108+35.5]=1300×143.5AgCl = \dfrac{1}{300} \times \left[108 + 35.5\right] = \dfrac{1}{300} \times 143.5
=0.48g= 0 .48 g
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