JEE Main2018ChemistrySome Basic Concepts of ChemistryActual
The ratio of mass percent of C and H of an organic compound C X H Y O Z is 6 : 1 . If one molecule of the above compound C X H Y O Z contains half as much oxygen as required to burn one molecule of compound C X H Y completely to CO 2 and H 2 O . The empirical formula of the compound C X H Y O Z is
Options
- AC 2 H 4 O 3
- BC 3 H 6 O 3
- CC 2 H 4 O
- DC 3 H 4 O 2
Correct answer
A. C 2 H 4 O 3
Step-by-step solution
Mass of C : Mass of H = 6   :   1 . Or, for every atom of C   ( 12   u ) , we have 2   atoms of H   ( 1 u   ×   2 = 2 u ) Thus, the ratio of atoms of C   :   H = x   :   y = 1   :   2 Thus, the formula is: C x H 2 x O z Combustion of C x H 2 x : C x H 2 x + ( 3 x / 2 ) O 2 → xCO 2 + xH 2 O Hence, the combustion of C x H 2 x requires ( 3 x / 2 ) oxygen molecules. Hence, the original molecule contains ( 3 x / 4 )   molecules = ( 3 x