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5 ~g of benzene on nitration gave 6.6 ~g of nitrobenzene. The theoretical yield of the nitrobenzene will be

Options

  1. A4.5 ~g
  2. B5.6 ~g
  3. C8.09 ~g
  4. D6.6 ~g

Correct answer

C. 8.09 ~g

Step-by-step solution

C ₆ H ₆+ HNO ₃ C ₆ H ₅ NO ₂+ H ₂ O 78 ~g 123 ~g Now since 78 ~g of benzene on nitration give =123 ~g nitrobenzene hence 5 ~g of benzene on nitration give = 123 78 5=7.88 ~g nearest answer is (c) i.e. theoritical yield =7.88 ~g

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