5 ~g of benzene on nitration gave 6.6 ~g of nitrobenzene. The theoretical yield of the nitrobenzene will be

Correct answer: C. 8.09 ~g C_6 H_6+HNO_3 arrow C_6 H_5 NO_2+H_2 O 78 ~g 123 ~g Now since 78 ~g of benzene on nitration give =123 ~g nitrobenzene hence 5 ~g of benzene on nitration give =(123)/(78) × 5=7.88 ~g nearest answer is (c) i.e. theoritical yield =7.88 ~g

JEE Main 201212 MayOnline

Exam: JEE Main
Year: 2012
Date: 12 May
Mode: Online
Subject: Chemistry
Chapter: Some Basic Concepts of Chemistry

JEE Main 2012 · 12 May · Online · Chemistry · Some Basic Concepts of Chemistry

5 ~g of benzene on nitration gave 6.6 ~g of nitrobenzene. The...

5 \mathrm{~g}

of benzene on nitration gave

6.6 \mathrm{~g}

of nitrobenzene. The theoretical yield of the nitrobenzene will be

Options

A $4.5 \mathrm{~g}$
B $5.6 \mathrm{~g}$
C $8.09 \mathrm{~g}$
D $6.6 \mathrm{~g}$

Correct answer

C. $8.09 \mathrm{~g}$

Step-by-step solution

\mathrm{C}_6 \mathrm{H}_6+\mathrm{HNO}_3 \rightarrow \mathrm{C}_6 \mathrm{H}_5 \mathrm{NO}_2+\mathrm{H}_2 \mathrm{O}

78 \mathrm{~g} \quad 123 \mathrm{~g}

Now since

78 \mathrm{~g}

of benzene on nitration give

=123 \mathrm{~g}

nitrobenzene hence

5 \mathrm{~g}

of benzene on nitration give

=\frac{123}{78} \times 5=7.88 \mathrm{~g}

nearest answer is (c) i.e. theoritical yield

=7.88 \mathrm{~g}

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