An aqueous solution of oxalic acid dihydrate contains its 6.3 ~g in 250 ml . The volume of 0.1 ~N NaOH required to completely neutralize 10 ml of this solution

Correct answer: D. 40 ml Normality of oxalic acid solution = (6.3 × 1000)/(63 × 250)= 0.4 ~N Now from aligned & N_1 V_1=N_2 V_2 & 0.4 ×10=0.1 _2 & V_2=40 ~mL aligned

JEE Main 201212 MayOnline

Exam: JEE Main
Year: 2012
Date: 12 May
Mode: Online
Subject: Chemistry
Chapter: Some Basic Concepts of Chemistry

JEE Main 2012 · 12 May · Online · Chemistry · Some Basic Concepts of Chemistry

An aqueous solution of oxalic acid dihydrate contains its 6.3 ~g in...

An aqueous solution of oxalic acid dihydrate contains its

6.3 \mathrm{~g}

250 \mathrm{ml}

. The volume of

0.1 \mathrm{~N}

\mathrm{NaOH}

required to completely neutralize

10 \mathrm{ml}

of this solution

Options

A $4 \mathrm{ml}$
B $20 \mathrm{ml}$
C $2 \mathrm{ml}$
D $40 \mathrm{ml}$

Correct answer

D. $40 \mathrm{ml}$

Step-by-step solution

Normality of oxalic acid solution =

\frac{6.3 \times 1000}{63 \times 250}=

0.4

\mathrm{~N}

Now from

\begin{aligned}& N_1 V_1=N_2 V_2 \\ & 0.4 \times10=0.1 \timesV_2 \\ & V_2=40 \mathrm{~mL} \end{aligned}

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