The enthalpy change for the conversion of 1 2 Cl 2 (g) to Cl - ( aq ) is ( - ) kJmol - 1 (Nearest integer) Given : Δ dis H Cl 2 ( g ) 0 = 240 kJmol - 1 . Δ eg H Cl ( g ) o = - 350 kJmol - 1 , Δ hyd H Cl ( g ) - o = - 380 kJmol - 1

Step-by-step solution

1 2 Cl 2 (   g )   →   Cl ( g )   →   Cl ( g ) -   →   Cl ( aq . ) - Apply Hess's law, ∆ H   =   1 2   ∆ dis   H Cl 2   ( g ) 0   +   ∆ eg H Cl ( g ) o   +   ∆ hyd H Cl ( g ) - o ⇒   ∆ H = 1 2 ×   240   +   ( - 350 )   +   ( - 380 ) ⇒   ∆ H   =   - 610