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A fish swimming in water body when taken out from the water body is covered with a film of water of weight 36   g . When it is subjected to cooking at 100   ° C , then the internal energy for vaporization in kJmol - 1 is integer] [Assume steam to be an ideal gas. Given Δ vap H ⊖ for water at 373   K and 1 bar is 41 . 1   kJ   mol - 1 : R = 8 . 31   J   K - 1   m

Correct answer

38

Step-by-step solution

Weight of water on fish = 36 gram H 2 O l → P = 1 bar T = 100   ° C H 2 O g ; ΔH vap = 41 . 1   kJ   mole - 1 ΔH = ΔU = Δn g RT 41 . 1 × 2 = ΔU + 2 × 8 . 314 1000 373 ΔU = 82 . 2 - 6 . 2 = 76 kJ so change in internal energy in   kJ / mol = 76 2 = 38 kJ / mole

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