At 25 ° C, 50g of iron reacts with HCl to form FeCl _ 2 . The...

$T = 298K, R = 8 . 314\dfrac{J}{molK}$

$\to$ Chemical reaction is

$\mathop{Fe}_{50g} + 2HCl \to \mathop{{FeCl}_{2}}_{P = 1bar} + {H}_{2}\left(g\right)$

$= \dfrac{50}{55 . 85}mol$

$\to$ Work done for $1mol$ gas

$= - {P}_{ext} \times \Delta V$

$= {\Delta n}_{g}RT$

$= - 1 \times 8 . 314 \times 298J$

$\to$ Work done for $\dfrac{50}{55 . 85}$ mol of gas

$= - 8 . 314 \times 298 \times \dfrac{50}{55 . 85}J$

$= - 2218 . 059J$

$≃ - 2218J$