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JEE Main 202125 FebruaryMorning Shift
Exam
JEE Main
Year
2021
Date
25 February
Shift
Morning Shift
Subject
Mathematics
Chapter
Limits

JEE Main 2021 · 25 February · Morning Shift · Mathematics · Limits

_ n → ∞ (1 + 1 + (1)/(2) + + (1)/(n) n ^ 2 ) ^ n is equal to

lim⁡n→∞(1+1+12+……+1nn2)nisequalto\lim_{n \to \infty}{\left(1 + \dfrac{1 + \dfrac{1}{2} + \ldots \ldots + \dfrac{1}{n}}{{n}^{2}}\right)}^{n} is equal to

Options

  1. A1e\dfrac{1}{e}
  2. B00
  3. C12\dfrac{1}{2}
  4. D11

Correct answer

D. 11

Step-by-step solution

It is 1∞{1}^{\infty} form

L = {e}^{\lim_{n \to \infty}\left(\dfrac{\left1 + \dfrac{1}{2} + \dfrac{1}{3} + \ldots . . + \dfrac{1}{n}\right)}{n}\right)}

L=elim⁡n→∞(1n+12n+13n+…..+1n2)L = {e}^{\lim_{n \to \infty}\left(\dfrac{1}{n} + \dfrac{1}{2n} + \dfrac{1}{3n} + \ldots . . + \dfrac{1}{{n}^{2}}\right)}

∴L=e(0+0+0+…..+0)∴ L = {e}^{\left(0 + 0 + 0 + \ldots . . + 0\right)}

⇒L=e0=1⇒ L = {e}^{0} = 1

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