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JEE Main2005MathematicsLimitsActual

Let and be the distinct roots of a x^2+b x+c=0 , then _ x 1- (a x^2+b x+c ) (x- )^2 is equal to

Options

  1. Aa^2 2 ( - )^2
  2. B0
  3. C- a^2 2 ( - )^2
  4. D1 2 ( - )^2

Correct answer

A. a^2 2 ( - )^2

Step-by-step solution

aligned & Given limit = _ x 1- a(x- )(x- ) (x- )^2 = _ x 2 ^2 (a (x- )(x- ) 2 ) (x- )^2 & = _ x 2 (x- )^2 ^2 (a (x- )(x- ) 2 ) a^2(x- )^2(x- )^2 a^2(x- )^2(x- )^2 4 & = a^2( - )^2 2 . aligned

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