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JIPMER 2019
Exam
JIPMER
Year
2019
Subject
Chemistry
Chapter
Coordination Compounds

JIPMER 2019 · Chemistry · Coordination Compounds

Which one follow 18 electron octet rule?

Which one follow 18 electron octet rule?

Options

  1. A[Mn(CO)5]\left[\mathrm{Mn}(\mathrm{CO})_5\right]
  2. B[Cr(CO)5]\left[\mathrm{Cr}(\mathrm{CO})_5\right]
  3. C[Fe(CO)5]\left[\mathrm{Fe}(\mathrm{CO})_5\right]
  4. DNone of these

Correct answer

C. [Fe(CO)5]\left[\mathrm{Fe}(\mathrm{CO})_5\right]

Step-by-step solution

The 18 electron rule is used for predicting the stability and rationalizing the formula, especially organomettalic complexes. The number of valence electrons of the given species are as follows: [Mn(CO)5]−Mn{[Ar]183 d54 S2}=7 valence \left[\mathrm{Mn}(\mathrm{CO})_5\right]-\mathrm{Mn}\left\{[\mathrm{Ar}]_{18} 3 \mathrm{~d}^5 4 \mathrm{~S}^2\right\}=7 \text{ valence } electrons [Cr(CO)5]−Cr⁡{[Ar]183 d44 S2}=6 valence \left[\mathrm{Cr}(\mathrm{CO})_5\right]-\operatorname{Cr}\left\{[\mathrm{Ar}]_{18} 3 \mathrm{~d}^4 4 \mathrm{~S}^2\right\}=6 \text{ valence } electrons [Fe(CO)5]−Fe{[Ar]183 d64 S2}=8 valence \left[\mathrm{Fe}(\mathrm{CO})_5\right]-\mathrm{Fe}\left\{[\mathrm{Ar}]_{18} 3 \mathrm{~d}^6 4 \mathrm{~S}^2\right\}=8 \text{ valence } electrons ∴[Fe(CO)5]\therefore\left[\mathrm{Fe}(\mathrm{CO})_5\right] follow 18 electron octet rule.
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