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JIPMER 2004
Exam
JIPMER
Year
2004
Subject
Chemistry
Chapter
Coordination Compounds

JIPMER 2004 · Chemistry · Coordination Compounds

Oxidation number Fe in .K_3[Fe(CN)_6] is

Oxidation number Fe in K3[Fe(CN)6]\left.\mathrm{K}_3[\mathrm{Fe(CN)}_6\right] is

Options

  1. A+1
  2. B+2
  3. C+3
  4. D+4

Correct answer

C. +3

Step-by-step solution

Let, oxidation number of Fe be ' xx ' ∴3(+1)+x+6(−1)=03+x−6=0x=+3\begin{aligned} \therefore \quad 3(+1)+x+6(-1) & =0 \\ 3+x-6 & =0 \\ x & =+3\end{aligned}
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