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AIIMS 2001
Exam
AIIMS
Year
2001
Subject
Chemistry
Chapter
Chemical Bonding and Molecular Structure

AIIMS 2001 · Chemistry · Chemical Bonding and Molecular Structure

Which of the following option w.r.t. increasing bond order is...

Which of the following option w.r.t. increasing bond order is correct ?

Options

  1. ANO<C2<O2−<He2+\mathrm{NO} < \mathrm{C}_2 < \mathrm{O}_2^{-} < \mathrm{He}_2^{+}
  2. BC2<NO<He2+<O2−\mathrm{C}_2 < \mathrm{NO} < \mathrm{He}_2^{+} < \mathrm{O}_2^{-}
  3. CHe2+<O2−<NO<C2\mathrm{He}_2^{+} < \mathrm{O}_2^{-} < \mathrm{NO} < \mathrm{C}_2
  4. DHe2+<O2−<C2<NO\mathrm{He}_2^{+} < \mathrm{O}_2^{-} < \mathrm{C}_2 < \mathrm{NO}.

Correct answer

D. He2+<O2−<C2<NO\mathrm{He}_2^{+} < \mathrm{O}_2^{-} < \mathrm{C}_2 < \mathrm{NO}.

Step-by-step solution

Bond order of the molecules : \mathrm{O}}_{2}^{-}: K K(\sigma2 s)^2\left(\sigma_2 *\right)^2\left(\sigma2 p_{\mathrm{z}}\right)^2\left(\pi2 p_{\mathrm{x}}\right)^2\left(\pi2 p_{\mathrm{y}}\right)^2\left(\pi^* 2 p_x\right)^2\left(\pi^* 2 p_y\right)^1 Bond order of \mathrm{O}_2^{-}=\frac{1}{2}(8-5)=1.5He2+5\mathrm{He}_2^{+}:(σ(\sigma1 s)^2\left(\sigma^*1 s\right)^1BondorderofHe2+=12(Bond order of \mathrm{He}_2^{+}=\frac{1}{2}(2-1)=0.5C5\mathrm{C}}_{2}: K K(σ\sigma2 s)^2\left(\sigma^* 2 s\right)^2\left(\pi2 pxp_{\mathrm{x}}\right)^2\left(\pi22p_{\mathrm{y}}\right)^2 Bond order=\frac{1}{2}(6-2)=2.0\text{ NO : }KK(K K(\sigma2 s)^2\left(\sigma^* 2 s\right)^2\left(\sigma22p_{\mathrm{z}}\right)^2\left(\pi2^2 pxp_{\mathrm{x}}\right)^2\left(\pi222^2p_{\mathrm{y}}\right)^2\left(\pi* 2 pxp_{\mathrm{x}}\right)^1 Bond order =12(8−3)=2.5=\frac{1}{2}(8-3)=2.5
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