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JEE Main
Exam
JEE Main
Subject
Chemistry
Chapter
Solid State

JEE Main · Chemistry · Solid State

Two elements X and Y form two different compounds having formulas...

Two elements X\text{X} and Y\text{Y} form two different compounds having formulas X5Y2\text{X}_5\text{Y}_2 and XY2\text{XY}_2. The atomic mass of element X\text{X} is twice the atomic mass of element Y\text{Y}. If equal masses of both the compounds are taken, the ratio of the number of moles of XY2\text{XY}_2 to the number of moles of X5Y2\text{X}_5\text{Y}_2 is _____.

Correct answer

3

Step-by-step solution

Let the atomic mass of element Y\text{Y} be MM.

The atomic mass of element X\text{X} is 2M2M.

Molar mass of X5Y2=5(2M)+2(M)=12M\text{X}_5\text{Y}_2 = 5(2M) + 2(M) = 12M.

Molar mass of XY2=1(2M)+2(M)=4M\text{XY}_2 = 1(2M) + 2(M) = 4M.

Let the given mass of each compound be ww.

Number of moles of X5Y2\text{X}_5\text{Y}_2, n1=w12Mn_1 = \dfrac{w}{12M}.

Number of moles of XY2\text{XY}_2, n2=w4Mn_2 = \dfrac{w}{4M}.

Ratio of moles = n2n1=w4Mw12M=124=3\dfrac{n_2}{n_1} = \dfrac{\dfrac{w}{4M}}{\dfrac{w}{12M}} = \dfrac{12}{4} = 3.

Answer: 33
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