JEE MainChemistryCoordination Compounds
Match List I with List II. List I (Complex) List II (Spin-only magnetic moment in BM) A. [V(H₂O)₆]²⁺ I. 0 B. [FeF₆]³⁻ II. 2.83 C. [Co(ox)₃]³⁻ III. 3.87 D. [Ni(NH₃)₆]²⁺ IV. 4.90 V. 5.92 Choose the correct answer from the options given below:
Options
- AA-III, B-V, C-I, D-II
- BA-III, B-V, C-IV, D-I
- CA-II, B-IV, C-I, D-V
- DA-III, B-IV, C-IV, D-II
Correct answer
A. A-III, B-V, C-I, D-II
Step-by-step solution
A. [V(H₂O)₆]²⁺ : V²⁺ has a 3d^3 configuration. Number of unpaired electrons, n = 3 . Spin-only magnetic moment, = 3(3+2) = 15 3.87 BM. B. [FeF₆]³⁻ : Fe³⁺ has a 3d^5 configuration. F^- is a weak field ligand, so the electrons do not pair up. n = 5 . = 5(5+2) = 35 5.92 BM. C. [Co(ox)₃]³⁻ : Co³⁺ has a 3d^6 configuration. Oxalate ( ox²⁻ ) acts as a strong field ligand for Co³⁺ , causing complete pairing. n = 0 . = 0 BM. D. [Ni(NH₃)₆]²⁺ : Ni²⁺ has a 3d^8 configuration. In an octahedral field, d^8 will always have 2 unpa