Consider the brown ring complex formulated as [Fe(H₂O)₅(NO)]SO₄ . Let x be the oxidation state of the central metal ion, y be the number of unpaired electrons, and z be the number of electrons in its t_ 2g orbitals. The value of x + y + z is

Step-by-step solution

In the brown ring complex [Fe(H₂O)₅(NO)]SO₄ , the NO ligand is present as the nitrosonium ion, NO^+ . Let the oxidation state of Fe be x . x + 5(0) + (+1) = +2 x = +1 . So, the oxidation state of Fe is +1 . The electronic configuration of Fe atom is [Ar] 3d^6 4s^2 . For Fe^+ , the configuration is [Ar] 3d^7 . Due to the presence of five weak field H₂O ligands, the complex is high spin ( _o The 7 electrons in the 3d subshell are distributed as t_ 2g ^5 e_g^2 . Number of unpaired electrons, y = 3 (one in t_ 2g and tw