JEE MainChemistryCoordination Compounds
Among the following tetrahedral complexes, which one has the highest magnitude of crystal field stabilization energy (CFSE)?
Options
- A[ NiCl ₄]²⁻
- B[ CoCl ₄]²⁻
- C[ FeCl ₄]²⁻
- D[ MnCl ₄]²⁻
Correct answer
B. [ CoCl ₄]²⁻
Step-by-step solution
For tetrahedral complexes, the crystal field splitting is inverted compared to octahedral complexes, with the e set at a lower energy ( -0.6 _t ) and the t₂ set at a higher energy ( +0.4 _t ). Tetrahedral complexes are generally high-spin. The oxidation state of the metal in all given complexes is +2 . 1. [ MnCl ₄]²⁻ : Mn ²⁺ is 3d^5 . Configuration: e^2 t₂^3 . CFSE = [2 (-0.6) + 3 (0.4)] _t = 0 2. [ FeCl ₄]²⁻ : Fe ²⁺ is 3d^6 . Configuration: e^3 t₂^3 . CFSE = [3 (-0.6) + 3 (0.4)] _t = -0.6 _t 3. [ CoCl ₄]²⁻ : Co ²⁺