JEE MainChemistryCoordination Compounds
Find the number of complexes which have an odd number of electrons in their t₂ orbitals among the following: [ FeCl ₄]⁻, [ CoCl ₄]²⁻, [ NiCl ₄]²⁻, [ CuCl ₄]²⁻, [ ZnCl ₄]²⁻
Options
- A2
- B0
- C3
- D4
Correct answer
C. 3
Step-by-step solution
In tetrahedral complexes, the d -orbitals split into a lower energy e set and a higher energy t₂ set. Tetrahedral complexes are generally high-spin. For [ FeCl ₄]⁻ : Fe is in +3 oxidation state ( 3d^5 ). Configuration is e^2 t₂^3 . Number of t₂ electrons = 3 (odd). For [ CoCl ₄]²⁻ : Co is in +2 oxidation state ( 3d^7 ). Configuration is e^4 t₂^3 . Number of t₂ electrons = 3 (odd). For [ NiCl ₄]²⁻ : Ni is in +2 oxidation state ( 3d^8 ). Configuration is e^4 t₂^4 . Number of t₂ electrons = 4 (even). For [ CuCl ₄]²⁻ :