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Two octahedral complexes of Mn ²⁺ are formed with two different ligands. The spin-only magnetic moment of the first complex is 5.92 B.M. and that of the second complex is 1.73 B.M. The difference in the magnitude of their Crystal Field Stabilization Energies (CFSE), ignoring pairing energy, is:

Options

  1. A2.4 ₀
  2. B1.6 ₀
  3. C2.0 ₀
  4. D1.0 ₀

Correct answer

C. 2.0 ₀

Step-by-step solution

The central metal ion is Mn ²⁺ , which has a 3d^5 electronic configuration. For the first complex, = 5.92 B.M. indicates n = 5 unpaired electrons. This corresponds to a high-spin octahedral complex with the configuration t_ 2g ^3 e_g^2 . Its CFSE is [3 (-0.4) + 2 (0.6)] ₀ = 0 ₀ . For the second complex, = 1.73 B.M. indicates n = 1 unpaired electron. This corresponds to a low-spin octahedral complex with the configuration t_ 2g ^5 e_g^0 . Its CFSE is [5 (-0.4) + 0 (0.6)] ₀ = -2.0 ₀ . The magnitude of CFSE for the fi

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