Consider the following four coordination complexes: P = [ CoF ₆ ]³⁻ Q = [ RhF ₆ ]³⁻ R = [ NiCl ₄ ]²⁻ S = [ PtCl ₄ ]²⁻ The correct sequence representing the number of unpaired electrons present in P, Q, R, and S respectively is :

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Correct answer: A. 4, 0, 2, 0

We determine the number of unpaired electrons ( n ) for each complex by considering the metal's oxidation state, the d -electron count, and the ligand field strength, keeping in mind the periodic trends for 4d and 5d series metals. 1. P = [ CoF ₆ ]³⁻ : Co is in the +3 oxidation state, giving a 3d^6 configuration. F ^- is a weak field ligand, so the complex is high-spin ( t_ 2g ^4 e_g^2 ). The number of unpaired electrons is n = 4 . 2. Q = [ RhF ₆ ]³⁻ : Rh is in the +3 oxidation state, giving a 4d^6 configuration. M

Consider the following four coordination complexes: P = [ CoF ₆ ]³⁻ Q = [ RhF ₆ ]³⁻ R = [ NiCl ₄ ]²⁻ S = [ PtCl ₄ ]²⁻ The correct sequence representing the number of unpaired electrons present in P, Q, R, and S respectively is :

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