MHT CET Medical202622 April 2026Morning ShiftChemistryCoordination CompoundsActual
Find the hybridization and number of coordinate bonds formed in tetracyanonickelate(II) ion respectively.
Options
- Asp^3d^2 and 4 coordinate bonds
- Bdsp^2 and 4 coordinate bonds.
- Cdsp^2 and 2 coordinate bonds
- Dsp^3 and 2 coordinate bonds
Correct answer
B. dsp^2 and 4 coordinate bonds.
Step-by-step solution
The given complex ion is tetracyanonickelate(II), which is [Ni(CN)₄]²⁻ . The central metal ion is Ni in +2 oxidation state. The atomic number of Ni is 28, so the electronic configuration of Ni²⁺ is [Ar] 3d^8 . Since CN^- is a strong field ligand, it causes the pairing of the 3d electrons. The 8 electrons pair up to occupy four 3d orbitals, leaving one 3d orbital empty. The empty orbitals available for hybridization are one 3d , one 4s , and two 4p orbitals. Thus, the hybridization is dsp^2 , resulting in a square p