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MHT CET Medical202623 April 2026Evening ShiftPhysicsElectromagnetic InductionActual

A thin semicircular conducting ring of radius R is falling with its plane vertical in a horizontal magnetic induction B. At the position MNQ the speed of ring is V and emf developed across the ring is

Options

  1. Azero
  2. B2 RBV and Q is at higher potential
  3. CRBV and Q is at higher potential
  4. DBV R^2 2 and M is at higher potential

Correct answer

B. 2 RBV and Q is at higher potential

Step-by-step solution

The induced motional emf in an arbitrarily shaped moving conductor in a uniform magnetic field is equivalent to the emf induced in a straight conductor connecting its two ends. The effective length of the semicircular ring is the straight line distance between its ends M and Q. Effective length l = 2R The magnitude of the motional emf developed is given by = Bvl Substituting the values, we get = B V 2R = 2RBV To determine the polarity, we consider the magnetic force on a positive charge carrier, given by F = q( V B

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